Mathematics is an interesting subject, but students need to understand its concepts thoroughly. Most importantly, students need to practice Math problems regularly to enhance their understanding. They can take online learning help as this is personalized, understandable and easy to use. TutorVista offers online Math sessions to students of different academic standards. Moreover, word problems in Maths are confusing and students require detailed subject knowledge to solve Math word problems. TutorVista gives access to excellent Math tutors who help with step by step solutions to various difficult Math problems any time of the day or night. Should you need any assistance and progress in Math, TutorVista is here to help.

It has been observed that most students face difficulty while solving Math word problems. To tackle this problem, students can take online help for Math word problems. In brief, make your Math word problems easy by choosing beneficial online sessions offered by TutorVista. Expert tutors are associated with this site and hence, students get useful sessions on any desired topic. Word problems are found in different topics of Math like algebra, geometry and others. However, students can get requisite learning help for different Math topics by choosing online calculus help, geometry help, trigonometry help and others.

Choose sessions with TutorVista and solve your Math word problems in a step-by-step manner along with detailed explanations. Apart from this, students can get Math homework help and solutions of all complex Math problems exclusively.

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Solving Math word problems can be made easy and simple by following these steps:

### Ask until it gets clear

It is important to ask questions and get clarity on each Math concept. Once a new topic is introduced, students should understand it properly and then revise it in a systematic manner. If doubts arise, then they should be clearly resolved under the guidance of subject experts.

### Read it carefully

It is important to read the word problem carefully before solving them. Students may not understand the problem through quick reading.

### Break the problem into parts

Before solving a Math word problem it is important to break it into parts. Try and understand what you should do and what information has been provided in the problem.

### Solved Examples

**Question 1: **The sum of two positive integers is 31. If the sum of the square of these numbers is 625, find the largest of these numbers.

** Solution: **

Step 1: Let 'a' and 'b' be the two positive numbers. Then a + b = 31 and $a^2$ + $b^2$ = 625.

Step 2: Now we have two equations:

a + b = 31 ..........(1)

$a^2$ + $b^2$ = 625 .........(2)

Solve equation (1) for b

=> b = 31 - a

Put the result of b in equation (2)

$a^2$ + $(31 - a)^2$ = 625

$a^2$ + 961 + $a^2$ - 62$a$ = 625 [ $\because$ $(a - b)^2$ = $a^2$ + $b^2$ - 2ab]

2$a^2$ - 62$a$ + 336 = 0

or $a^2$ - 31$a$ + 168 = 0

By factorization, we get

a = 7 and a = 24

Step 3: Find the value of b

If a = 7 then b = 31 - 7 = 24

If a = 24 then b = 31 - 24 = 7

Therefore, the largest number be 24.

**Question 2: **The sides of a triangle are 8, 6 and 10. Check whether the given triangle is right triangle or not?

** Solution: **

Let a = 8, b = 6 and c = 10

By using converse of Pythagorean Theorem,

$c^2$ = $a^2$ + $b^2$

Solving this, we need to substitute the given values in above equation,

$10^2$ = $8^2$ + $6^2$

100 = 64 + 36

100 = 100

So, it satisfies the above condition.

Therefore, the given triangle is a right triangle.

Different types of math word problems are found in all branches of math:

1) Numbers word problems

2) Algebra word problems

3) Geometry word problems

4) Calculus word problems

5) Trigonometry word problems

6) Probability and Statistics word problems

Step 1: Let 'a' and 'b' be the two positive numbers. Then a + b = 31 and $a^2$ + $b^2$ = 625.

Step 2: Now we have two equations:

a + b = 31 ..........(1)

$a^2$ + $b^2$ = 625 .........(2)

Solve equation (1) for b

=> b = 31 - a

Put the result of b in equation (2)

$a^2$ + $(31 - a)^2$ = 625

$a^2$ + 961 + $a^2$ - 62$a$ = 625 [ $\because$ $(a - b)^2$ = $a^2$ + $b^2$ - 2ab]

2$a^2$ - 62$a$ + 336 = 0

or $a^2$ - 31$a$ + 168 = 0

By factorization, we get

a = 7 and a = 24

Step 3: Find the value of b

If a = 7 then b = 31 - 7 = 24

If a = 24 then b = 31 - 24 = 7

Therefore, the largest number be 24.

Let a = 8, b = 6 and c = 10

By using converse of Pythagorean Theorem,

$c^2$ = $a^2$ + $b^2$

Solving this, we need to substitute the given values in above equation,

$10^2$ = $8^2$ + $6^2$

100 = 64 + 36

100 = 100

So, it satisfies the above condition.

Therefore, the given triangle is a right triangle.

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