`sin2 a + cos2 a = 1`
`1 + tan2 a = sec2 a`
`1 + cot2 a = csc2 a`
`csc a = 1/ sin a`
`sec a = 1/ cos a`
`cot a = 1/ tan a`
`sin a = 1/csc a`
`cos a = 1/sec a`
`tan a = 1/cot a`
`tan a = sin a/cos a`
`cot a= cos a/sin a`
`sin(pi/2- a) = cos a`
`tan(pi/2- a) = cot a`
`sec(pi/2- a) = csc a`
`cos(pi/2- a) = sin a`
`cot(pi/2- a) = tan a`
`csc(pi/2- a) = sec a`
`cos(-a) = cos a`
`sin(-a) = -sin a`
`tan(-a) = -tan a`
`sec(-a) = sec a`
`csc(-a) = -csc a`
`cot(-a) = -cot a`
`sin(a + b) = sin a cos b + cos a sin b`
`tan(a + b) = (tan a+tan b)/(tan a tan b)`
`sin(a - b) = sin a cos b - cos a sin b`
`cos(a + b) = cos a cos b - sin a sin b`
`tan(a - b) = (tan a-tan b)/(1+tan a tan b)`
`cos(a - b) = cos a cos b + sin a sin b`
`sin(2a) = 2 sin a cos a`
`cos(2a) = cos^2 a - sin^2 a = 2 cos^2 a - 1 = 1 - 2 sin^2 a`
`tan(2a) = (2 tana)/(1-tan2 a)`
`sin a + sin b = 2 sin((a+b)/2 ) cos( (a-b)/2 )`
`sin a - sin b = 2 cos((a+b)/2 ) sin((a-b)/2 )`
`cos a + cos b = 2 cos((a+b)/2) cos(( a-b)/2 )`
`cos a - cos b = -2 sin((a+b)/2 ) sin((a-b)/2 )`
`(sinA)/(a) = sinB/(b) = sinC/(c)`
`a^2 = b^2 + c^2 - 2bc cosA`
`b^2 = a^2 + c^2 - 2ac cosB`
`c^2 = a^2 + b^2 - 2ab cosC`
Prove the trigonometric identities : `sin y + sin y cot2 y = csc y`
`sin y + sin y cot2 y`
By simplifying the given equation we get
= `sin y(1+ cot2 y)`
We know that `csc2y=1+cot2y`
`= sin y( csc2 y )`
We can write `csc2 y=1/(sin2y)`
`= (sin y )[(1)/(sin2 y)]`
By crossing the values we get,
`=1/sin y`
we know that `1/sin y= csc y`
`=csc y`
Hence the identity `sin y + sin y cot2 y = csc y` is proved.
Prove the identity:` tan a/sin a=sec a`
Simplify the terms in sin and cos.Then simplify
`tan a . 1/(sin a)`
The` tan a` can be put as `sin a/cos a`
`=(sin a)/(cos a). 1/(sin a)`
Cross out the values we get,
`=1/(cos a)`
We know that `1/cos a = sec a`
`=sec a`
Hence `tan a/sin a=sec a` is proved.