10th Grade Math Help
This is a representative list of topics covered in our Grade 10 Math program - however all programs will be customized for the individual student.
10th Grade Math Program:
Get help in understanding algebra, calculus, precalculus, geometry, trigonometry, statistics, probability, linear programming, and discrete mathematics covering the entire 10th Grade Math Curriculum with our online Math tutoring Program. Whether you need Math help or some quick assistance in solving Math problems before a test or an exam, our online Math tutors can help. Our tutors provide you with instant help, homework help and help with assignments in Math.
Important topics Covered under Grade 10th Math
- Algebra
- Liner Algebra
- Calculus
- Trigonometry
- Geometry
We feature, around 10000 problems & math printables that range in skill from grades K-12. Please use all of our solved examples in 10th grade Math lessons, and 10th Grade Math worksheets to make your day easier. Great for students, teachers, parents, and tutors.
Standard Math Curriculum- 10th Grade Math
Solved Examples
Solution:
Let Alica's age be represented with x and Aline's age represented with x + 10.
In 12 years:
Add 12 to both ages
Alica's age = x + 12 and Aline's age = (x + 10) + 12 = x + 22
The sum of their ages in 12 years will be 40, so the equation is as follows:
=> x + 12 + x + 22 = 40
=> 2x + 34 = 40
=> 2x = 40 - 34 = 6
or x = $\frac{6}{2}$ = 3
So Alica is 3, and Aline is 13 (i.e. 3 + 10).
Solution:
Given: 5m + 2n = 14 ..........(1)
2m - n = 2 ..............(2)
Use the substitution method to solve the given system
Step 1: Solve the second equation for n
=> n = 2m - 2
Substitute this solution for n in equation (1)
=> 5m + 2(2m - 2) = 14
Solve for m
5m + 4m - 4 = 14
9m = 18
or m = $\frac{18}{9}$ = 2
Step 2: Again substitute this solution for m in equation (2)
2 * 2 - n = 2
4 - n = 2
n = 2
The solution for the given system is (2, 2).
Practice Problems
Few problems based on geometry are given below:
Solved Examples
Solution:
Given that the angle is 130$^o$ and its radius is 10 cm.
The formula to find the area of segment of a circle is $\frac{r^2}{2}$ $((\frac{\pi}{180^o})$ $\theta$ - sin $\theta)$
Substitute the given values in the formula
= $\frac{r^2}{2}$ $((\frac{\pi}{180^o})$ $\theta$ - sin $\theta)$
= $\frac{10^2}{2}$ $((\frac{\pi}{180^o})$ $\times$ 130$^o$ - sin 130$^o$)
= 75.1 cm$^2$.
Solution:
As the pair 58$^o$, y and x, z are alternate interior angles, they are equal in measure.
So, y = 58$^o$
58$^o$ + x = 180$^o$ (Linear pair)
x = 180$^o$ - 58$^o$
= 122$^o$
Since x and z are alternate interior angles, they are equal in measure
So, z = 122$^o$.