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9th Grade Math Help
The 9th grade math help deals with all the important topics for the 9th grade students.This is a representative list of topics covered in our Grade 9 Math help - however all programs will be customized for the individual student. The students get help with the various topics under various branches on mathematics. Ninth grade students also get support to solve their homework problems and prepare for their exams with Math help. Get help with all grade 9 math topics with Tutorvista.
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Few 9th Grade Math Problems are as follows:
Practice problems based on 9th grade math are given below :
Solved Examples
Question 1: The sum of the age of two sisters is 31. The younger sister was 3 years
younger than the older sibling five years ago. How old are they now?
Solution:
Let the age of two sisters x and y (Let us assume that y is younger sister).
Since sum of the age of two sisters is 31, So x + y = 31
x + y = 31 ............(1)
Five years ago:
The age of two sisters x - 5 and y - 5
Now
y - 5 = (x - 5) - 3
y - 5 = x - 8
or y = x - 3 ....(2)
Substitute the value of y in equation (1)
x + x - 3 = 31
2x = 34
or x = 17
Again substitute the value of x in equation (2)
y = 17 - 3 = 14
Therefore both the sisters are of 14 and 17.
Solution:
Let the age of two sisters x and y (Let us assume that y is younger sister).
Since sum of the age of two sisters is 31, So x + y = 31
x + y = 31 ............(1)
Five years ago:
The age of two sisters x - 5 and y - 5
Now
y - 5 = (x - 5) - 3
y - 5 = x - 8
or y = x - 3 ....(2)
Substitute the value of y in equation (1)
x + x - 3 = 31
2x = 34
or x = 17
Again substitute the value of x in equation (2)
y = 17 - 3 = 14
Therefore both the sisters are of 14 and 17.
Question 2: A rectangular shape garden is 1 feet longer than it is wide and has area of 90 sq feet. Find the dimensions of the garden.
Solution:
Let x be the width of the garden, so x + 1 is the length.
Area of garden = 90 sq. feet (given)
We know that, Area of rectangle = Length $\times$ Width
=> 90 = x(x + 1)
x$^2$ + x - 90 = 0 (which is quadratic equation)
Solve for x
x$^2$ + 10x - 9x - 90 = 0
x(x + 10) - 9(x + 10) = 0
(x - 9)(x + 10) = 0
=> x = 9 or x = -10
Length can not be negative, so neglect x = -10
So x = 9, is the width of the garden and 10 is the length of the rectangular garden.
Solution:
Let x be the width of the garden, so x + 1 is the length.
Area of garden = 90 sq. feet (given)
We know that, Area of rectangle = Length $\times$ Width
=> 90 = x(x + 1)
x$^2$ + x - 90 = 0 (which is quadratic equation)
Solve for x
x$^2$ + 10x - 9x - 90 = 0
x(x + 10) - 9(x + 10) = 0
(x - 9)(x + 10) = 0
=> x = 9 or x = -10
Length can not be negative, so neglect x = -10
So x = 9, is the width of the garden and 10 is the length of the rectangular garden.
Practice Problems
Question 1: The sum of Jarina's and Jarin's age is 30. Two years ago, Jarin was 10 years older than her. How old are they now. (Answer: Jarin's age = 20 and Jarina's age = 10 years.)
Question 2: Solve for x; $\sqrt{x - 9}$ = 10 (Answer: x = 109)