Circle is defined as the set of points that is at an equal distant from the centre of the circle.
There are a number of terminologies involved in a Circle. Some of them are as follows:
Centre: The predetermined point from which the surface of the circle is at an equidistant is called the centre of a circle.
Radius: The constant distance from the centre to a point on the surface of the circle is called its radius .
Circumference: The boundary of a circle is called its circumference.
Chord: A line segment whose end points is present on the circumference of a circle is called a chord .
Diameter: A chord crossing through the midpoint of a circle is called its diameter.
Diameter of a Circle: Diameter = 2 X Radius
Radius of a Circle: Radius(R) = Diameter / 2
Area of a Circle: Area = pi X R2
Circumference of a Circle: Circumference = 2 X pi X R
Theorem 1: A perpendicular from the centre of a circle to a chord bisects the chord.
Given : AB is a chord in a circle with centre O. OC ⊥ AB.
To prove: The point C bisects the chord AB.
Construction: Join OA and OB
Proof: In triangles OAC and OBC,
m∠OCA = m∠OCB = 90 (Given)
OA = OB (Radii)
OC = OC (common side)
∠OAC = ∠OBC (RHS)
CA = CB (corresponding sides)
The point C bisects the chord AB.
Hence the theorem is proved.
Theorem 2: AB and CD are equal chords of a circle whose centre is O. OM ⊥ AB and ON ⊥ CD. Prove that m∠OMN = m∠ONM.
Given : In a circle with centre O chords AB and CD are equal
OM ⊥ AB, ON ⊥ CD (Fig.6.11).
To prove : ∠OMN = ∠ONM
Proof : AB = CD (given)
OM ⊥ AB (given); ON ⊥ CD (given)
OM = ON (equal chords equidistant from the centre)
In triangle OMN,
m∠OMN = m∠ONM ( Δ OMN is isosceles)
Hence Proved.