TutorVista is known for its efficient online sessions that make students confident and intelligent before their exams. The online tutoring service offered is convenient and prompt, any assistance related to math is just a click away. Proficient academicians associated with TutorVista provide assistance as per the student's learning requirements. Based on the academic standards, students can choose their topics and schedule their sessions anytime from home. Moreover, TutorVista offers personalized attention to students and also covers vast topics in each subject. Math is an important subject and students must practice Math thoroughly in order to score well in exams. TutorVista provides homework help for Math wherein students can choose unlimited sessions to make their exam preparation beneficial and effective.

By choosing 11th Grade Math tutoring programs of TutorVista, students can not only understand Math concepts, but also learn methods to solve difficult Math problems quickly and fluently. Online sessions offered by TutorVista are complete, competent and beneficial for students. The tutor and student talk to each other using voice (VoIP) and share different problems by using an interactive whiteboard. Moreover, students can complete their assessments and tasks by getting adequate help form virtual tutors. It is proved that one-on-one tutoring sessions are valuable as these are done under the supervision of skilled subject experts.

- Practice all Math chapters repeatedly by taking learning assistance from TutorVista.
- Solve all difficult Math problems while preparing for exams.
- Schedule unlimited online sessions to revise Math topics appropriately.
- Solve online worksheets and enhance your confidence in each topic.

TutorVista covers all important Math topics included in the Class 11 Math syllabus.

- Number System
- Algebra I
- Algebra II
- Pre Calculus
- Calculus
- Statistics
- Geometry
- Trigonometry
- Advanced Trigonometry

Students are advised to practice various Math problems to improve their subject knowledge.Class 11 includes important learning of most essential topics which includes algebra, sets and function, coordinate geometry, statistics and probability that are added in the syllabus. Students are advised to follow these topics thoroughly to score well in exams. Absolute knowledge in Math is a key for students to get prodigious jobs in different fields.

### Solved Examples

**Question 1: **Find first term of arithmetic progression whose 7th and 10th terms are 35 and 59 respectively.

** Solution: **

Let 'a' be the first term. Now we have to find the value of 'a' by using given instructions.

Given: 7th term, a$_7$ = 35 and 10th term, a$_{10}$ = 59

We know that the general term of AP is, a$_n$ = a + (n - 1)d

=> a$_7$ = a + 6d = 35

or a + 6d = 35 ...........(i)

and a$_{10}$ = a + 9d = 59

or a + 9d = 59 ..............(ii)

The value of 'a' can be found by subtracting equation (ii) from equation (i)

a + 6d = 35

a + 9d = 59

- - -

-----------------

-3d = -24

-----------------

=> d = 8

Substitute the result of d in equation (i)

a + 6 $\times$ 8 = 35

a + 48 = 35

a = -13

The value of a is -13.

**Question 2: **From 8 men and 5 women, four persons are being selected to form a committee
so that at least 2 women are available in the committee. In how many ways
can it be done?

** Solution: **

The possible number of ways are:

2 women and 2 men = $^5$C$_2$ $\times$ $^8$C$_2$ = 280

3 women and 1 man = $^5$C$_3$ $\times$ $^8$C$_1$ = 80

4 women only = $^5$C$_4$ = 5

So total number of ways = 280 + 80 + 5 = 365

TutorVista offers Class 11 solved Math examples for the convenience of students. Students can follow these examples and understand the solutions in a step-by-step manner. They can also practice online Math worksheets under the guidance of virtual tutors. ### Practice Problems

**Question 1: **Sum of first 4 terms of arithmetic progression is 28 and sum of first eight terms is 88. Find sum of first 10 terms. (Answer: S$_{10}$ = 130)

**Question 2: **Use induction to prove that, $\frac{1}{2}$ + $\frac{1}{4}$ +
$\frac{1}{8}$ + ......+ $\frac{1}{2^n}$ = $\frac{2^n - 1}{2^n}$.

Let 'a' be the first term. Now we have to find the value of 'a' by using given instructions.

Given: 7th term, a$_7$ = 35 and 10th term, a$_{10}$ = 59

We know that the general term of AP is, a$_n$ = a + (n - 1)d

=> a$_7$ = a + 6d = 35

or a + 6d = 35 ...........(i)

and a$_{10}$ = a + 9d = 59

or a + 9d = 59 ..............(ii)

The value of 'a' can be found by subtracting equation (ii) from equation (i)

a + 6d = 35

a + 9d = 59

- - -

-----------------

-3d = -24

-----------------

=> d = 8

Substitute the result of d in equation (i)

a + 6 $\times$ 8 = 35

a + 48 = 35

a = -13

The value of a is -13.

The possible number of ways are:

2 women and 2 men = $^5$C$_2$ $\times$ $^8$C$_2$ = 280

3 women and 1 man = $^5$C$_3$ $\times$ $^8$C$_1$ = 80

4 women only = $^5$C$_4$ = 5

So total number of ways = 280 + 80 + 5 = 365

Related Topics | |

Math Help Online | Online Math Tutor |