11th Grade Math Help
This is a representative list of topics covered in our Grade 11 Math program - however all programs will be customized for the individual student.
TutorVista's Online Math Tutoring gets you ahead
With TutorVista's online 11th Grade Math tutoring, students understand Math concepts and learn to solve math problems quickly and easily. TutorVista sessions are just like having a tutor besides you at home or in a classroom. The tutor and student talk to each other using voice (VoIP) and share an interactive whiteboard to work problems, simulations, assessments and other tasks. The one on one interactive session with the tutor helps you get an edge in the subject.
Tips to Achieve Grades
- Complete coverage of all topics as per the 11th Grade Standard Math Curriculum.
- Unlimited questions in more than 1000 skills covering the entire 11th Grade math lessons.
- Math is made simpler and easy, with 11th Grade Math Problems, and easy steps to follow.
- Online live tutor explaining step by step solution to problems.
- Helps students at any time around the clock regardless of place where they are located.
Remember that 11th Grade Math is very important, since all the topics will be the base for 12th Grade Preparations. Please , get into the theory, understand the logic and solve more examples to get a hold on the Subject.
Important topics covered under 11th Grade Math:
- Number System
- Algebra I
- Algebra II
- Pre Calculus
- Calculus
- Statistics
- Geometry
- Trigonometry
- Advanced Trigonometry
Solved Examples
Solution:
Let 'a' be the first term. Now we have to find the value of 'a' by using given instructions.
Given: 7th term, a$_7$ = 35 and 10th term, a$_{10}$ = 59
We know that the general term of AP is, a$_n$ = a + (n - 1)d
=> a$_7$ = a + 6d = 35
or a + 6d = 35 ...........(i)
and a$_{10}$ = a + 9d = 59
or a + 9d = 59 ..............(ii)
The value of 'a' can be found by subtracting equation (ii) from equation (i)
a + 6d = 35
a + 9d = 59
- - -
-----------------
-3d = -24
-----------------
=> d = 8
Substitute the result of d in equation (i)
a + 6 $\times$ 8 = 35
a + 48 = 35
a = -13
The value of a is -13.
Solution:
The possible number of ways are:
2 women and 2 men = $^5$C$_2$ $\times$ $^8$C$_2$ = 280
3 women and 1 man = $^5$C$_3$ $\times$ $^8$C$_1$ = 80
4 women only = $^5$C$_4$ = 5
So total number of ways = 280 + 80 + 5 = 365