Top

This is a representative list of topics covered in our Grade 11 Math program - however all programs will be customized for the individual student.

TutorVista's Online Math Tutoring gets you ahead

With TutorVista's online 11th Grade Math tutoring, students understand Math concepts and learn to solve math problems quickly and easily. TutorVista sessions are just like having a tutor besides you at home or in a classroom. The tutor and student talk to each other using voice (VoIP) and share an interactive whiteboard to work problems, simulations, assessments and other tasks. The one on one interactive session with the tutor helps you get an edge in the subject.

• Complete coverage of all topics as per the 11th Grade Standard Math Curriculum.
• Unlimited questions in more than 1000 skills covering the entire 11th Grade math lessons.
• Math is made simpler and easy, with 11th Grade Math Problems, and easy steps to follow.
• Online live tutor explaining step by step solution to problems.
• Helps students at any time around the clock regardless of place where they are located.

Remember that 11th Grade Math is very important, since all the topics will be the base for 12th Grade Preparations. Please , get into the theory, understand the logic and solve more examples to get a hold on the Subject.

Important topics covered under 11th Grade Math:

• Number System
• Algebra I
• Algebra II
• Pre Calculus
• Calculus
• Statistics
• Geometry
• Trigonometry

Below are some 11th grade problems:

Solved Examples

Question 1: Find first term of arithmetic progression whose 7th and 10th terms are 35 and 59 respectively.
Solution:

Let 'a' be the first term. Now we have to find the value of 'a' by using given instructions.

Given:  7th term, a$_7$ = 35 and 10th term, a$_{10}$ = 59

We know that the general term of AP is, a$_n$ = a + (n - 1)d

=> a$_7$ = a + 6d = 35

or  a + 6d = 35  ...........(i)

and a$_{10}$ = a + 9d = 59

or a + 9d = 59  ..............(ii)

The value of 'a' can be found by subtracting equation (ii) from equation (i)

a + 6d = 35

a + 9d = 59
-      -      -
-----------------
-3d = -24
-----------------

=> d = 8

Substitute the result of d in equation (i)

a + 6 $\times$ 8 = 35

a + 48 = 35

a = -13

The value of a is -13.

Question 2: From 8 men and 5 women, four persons are be selected to form a committee so that at least 2 women are there on the committee. In how many ways can it be done.
Solution:

The possible number of ways are:

2 women and 2 men = $^5$C$_2$ $\times$ $^8$C$_2$ = 280

3 women and 1 man = $^5$C$_3$ $\times$ $^8$C$_1$ = 80

4 women only = $^5$C$_4$ = 5

So total number of ways = 280 + 80 + 5 = 365

Question 1: Sum of first 4 terms of arithmetic progression is 28 and sum of first eight terms is 88. Find sum of first 10 terms. (Answer: S$_{10}$ = 130)
Question 2: Use induction to prove that, $\frac{1}{2}$ + $\frac{1}{4}$ + $\frac{1}{8}$ + ......+ $\frac{1}{2^n}$ = $\frac{2^n - 1}{2^n}$.