Algebra Mixture Problems

Algebra mixture problems are the problems which derive at a final solution by adding solution of two or more results of the same problem.

A given algebra word problem consists of data which are arranged to solve part by part and then to derive at solution for the end results of each part is mixed.

Solving Algebra Mixture Problem

Finding how many liters of a solution that is 20% alcohol should be combined with 10 liters of a solution that is 50% alcohol to create a solution that is 30% alcohol? .

Solution:

The primary technique that we will develop here is to trace the target ingredient in the problem. In this problem the target ingredient is alcohol. In future problems it might be antifreeze or acid. The equation will state that the amount of alcohol in the first container and the amount of alcohol in the second will equal the amount of alcohol in the final mixture.

The amount of alcohol in the first container plus the amount of alcohol in the second container equals the amount of alcohol in the final mixture. The equation is in the final column is written as.

Table Showing Final Mixture

	PERCENT	AMOUNT OF SOLUTION	AMOUNT OF TARGET
1ST CONTAINER	0.50	10	5
2ND CONTAINER	0.24	X	0.20X
MIXTURE	0.30	X + 10	0.30 ( X + 10 )

Now we solve the equation

5 + 0.20x = 0.30(x + 10).

5 + 0.20x = 0.30x + 3

Take - 0.20x on both the sides

5 + 0.20x - 0.20x = 0.30x + 3 - 0.20x

5 = 0.10x + 3

5 - 3 = 0.10x + 3 - 3

$\frac{2}{0.10}$ = $\frac{0.10x}{0.10}$

X = 20.

Algebra Mixture Problems Example

1. How many ounces of a solution that is 10% alcohol should be mixed with 12 ounces of a solution that is is 24% alcohol to create a solution that is 15% alcohol?

On solving algebra work problems like the above one can derrive at required solution with correct values as mentioned in the table.

Final algebra mixture table